section quantity in section name

[webmaster]

Hi, i am trying to get the number of child sections to display on a section name....i am using the javascript yahoo menu....and on my subsections i want to display how many sections are inside it like section name (3)

i tried using this method

ar[i].pChild.length

which works and shows how many section are in the current section but i need how many are in the third subsection...the ones which arent generated in the script......so basically i need something like

ar[i].pChild.pChild.length

but this doesnt work....im sure norman would know if he is around

help woulod be greatly appreciated

[NormanRouxel]

On holiday in the Canaries (if Jo's listening - in Corralejo - with big waves), with only limited resources.

Suggest you look at the YahooSections code and make a new inner loop based on the second-level one.

UPDATE. Something like this (YahooSections expanded to 3 levels) - you'll have to add in the count display yourself:

function YahooSections(ar)
{
var strIDs = '';
for (var i=1;i<=ar.length;i++)
  {
  if (ar[i].sURL != null)
    {
    strIDs += '<a href="' + directURL(ar[i].sURL) + '"><span class="actxxsmall"><font color="NETQUOTEVAR:FGCOLORCSS">' + ar[i].sName + '</font></span></a><br>';
      {
      if (ar[i].pChild)
        {
        for (var j=1;j<=ar[i].pChild.length;j++)
          {
          if (ar[i].pChild[j].sURL != null)
            {
            strIDs += '--<a href="' + directURL(ar[i].pChild[j].sURL) + '"><span class="actxxsmall"><font color="NETQUOTEVAR:FGCOLORCSS">' + ar[i].pChild[j].sName + '</font></span></a><br>';
	    if (ar[i].pChild[j].pChild)
              {
              for (var k=1;k<=ar[i].pChild[j].pChild.length;k++)
                {
                strIDs += '----<a href="' + directURL(ar[i].pChild[j].pChild[k].sURL) + '"><span class="actxxsmall"><font color="NETQUOTEVAR:FGCOLORCSS">' + ar[i].pChild[j].pChild[k].sName + '</font></span></a><br>';
                }
              }
            }
          }
        }
      }
    strIDs += '<br>'
    }
  }
return strIDs
}

[webmaster]

Thanks Norman....although i dont actually need the third section displaying...i just need to know how many sections there are.

the problem is im using a slashdot style drop menu...so i've customised it slightly........basically i need var [j] and var[k] to be displayed together but if i put it in the order you shoed var[k] is declared after the second section so im not sure how i get k into the second menu.....heres my current script.

<script type="text/javascript" src="sdmenu.js">
		/***********************************************
		* Slashdot Menu script- By DimX
		* Submitted to Dynamic Drive DHTML code library: [url]http://www.dynamicdrive.com[/url]
		* Visit Dynamic Drive at [url]http://www.dynamicdrive.com/[/url] for full source code
		***********************************************/
	</script>
    <script type="text/javascript">
	// <![CDATA[
	var myMenu;
	window.onload = function() {
		myMenu = new SDMenu("my_menu");
		myMenu.init();
	};
	// ]]>
	</script>
<SCRIPT LANGUAGE="JavaScript" TYPE="text/javascript">
<!--
function YahooSections(ar)
{
var strIDs = '';
for (var i=1;i<=ar.length;i++)
  {
  if (ar[i].sURL != null)
    {
	strIDs += '<div class="collapsed">';
	strIDs += '<span><a href="#" class="top_section">' + ar[i].sName + '</a></span>';
      {
      if (ar[i].pChild)
        {
        for (var j=1;j<=ar[i].pChild.length;j++)
          {
          if (ar[i].pChild[j].sURL != null)
            {
            strIDs += '<a href="' + ar[i].pChild[j].sURL + '" class="sub_section">' + ar[i].pChild[j].sName +'</a>';
if (j==ar[i].pChild.length)
{strIDs += '</div>';
}

if (ar[i].pChild[j].pChild)
              {
              for (var k=1;k<=ar[i].pChild[j].pChild.length;k++)
                {
                strIDs += ''+ ar[i].pChild[j].pChild[k].sName + '';
                }
              }
            }
          }
        }
      }
    strIDs += ''
    }
  }
return strIDs
}
</SCRIPT>

ive currently got the third section dumped at the bottom...it displays but i need to know how to get the number of sections from [k] into what is displayed by [j]

hope that makes sense......dont worry if you busy to look further at this.....i'd probably figure it eventually....would just take me ages of trial and error

[NormanRouxel]

Sorry. I won't be able to look at this.